x^2-4x+161=8x

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Solution for x^2-4x+161=8x equation: 



x^2-4x+161=8x

We move all terms to the left:

x^2-4x+161-(8x)=0

We add all the numbers together, and all the variables

x^2-12x+161=0

a = 1; b = -12; c = +161;
Δ = b2-4ac
Δ = -122-4·1·161
Δ = -500
Delta is less than zero, so there is no solution for the equation

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